US > Indiana > Steuben County > Indian Hills

Indian Hills (in Steuben County, IN) Populated Place Profile

Indian Hills: Basic Facts & Information

Indian Hills is a populated place located within the Township of Jackson, a minor civil division (MCD) of Steuben County.

The elevation of Indian Hills is 1,014 feet. Indian Hills appears on the Stroh U.S. Geological Survey Map. Steuben County is in the Eastern Time Zone (UTC -5 hours).

Steuben County: Subdivisions (MCDs) | Cities & Towns | ZIP Codes | Features (airports, churches, hospitals, etc.)

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Mapped Location of Indian Hills

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Nearby Cities, Towns & Census Designated Places

Hudson, IN (7.2 miles SSE)
Orland, IN (7.5 miles N)
Ashley, IN (8.1 miles SE)
Ashley, IN (8.1 miles SE)
Angola, IN (8.1 miles E)

Wolcottville, IN (12.8 miles WSW)
Wolcottville, IN (12.8 miles WSW)
Corunna, IN (12.8 miles S)
Lagrange, IN (13.5 miles W)
Fremont, IN (13.8 miles ENE)

Nearby Neighborhoods, Subdivisions & Other Small Populated Places

Flint, IN (2.4 miles NE)
Salem Center, IN (2.7 miles SSE)
Westview, IN (2.7 miles SSW)
Wildwood, IN (2.7 miles SW)
Lakeside Park, IN (3.1 miles SW)

Oak Lodge, IN (3.1 miles SW)
Elmira, IN (3.4 miles SW)
Meadow Shores Park, IN (3.4 miles SSW)
Sha-Get Acres, IN (3.6 miles SSW)
Stroh, IN (3.6 miles SW)