Lakewood Hills (in Vanderburgh County, IN) Populated Place Profile

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Lakewood Hills: Basic Facts & Information

Lakewood Hills is a populated place LOCATED WITHIN the City of Evansville. In turn, the City of Evansville is located within Vanderburgh County.

Lakewood Hills is located at latitude 38.002 and longitude -87.514. The elevation of Lakewood Hills is 387 feet above mean sea level.

Since Lakewood Hills is located within the City of Evansville, all of the census and demographic data for residents of Lakewood Hills are included as part of the information reported for City of Evansville in the "Profile" tab above.

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Nearby Cities, Towns & Census Designated Places

Melody Hill, IN (1.4 miles N)
Evansville, IN (3.1 miles SW)
Highland, IN (4.1 miles NW)
Newburgh, IN (7.1 miles SE)
Darmstadt, IN (7.6 miles NNW)
Chandler, IN (8.4 miles ENE)
Spottsville, KY (11.4 miles SSE)
Elberfeld, IN (11.4 miles NNE)
Parkers Settlement, IN (11.4 miles WNW)
Henderson, KY (12.2 miles SSW)

Nearby Neighborhoods, Subdivisions & Other Small Populated Places

Smythe, IN (1.4 miles ESE)
Knob Hill, IN (1.9 miles N)
Erskine Station, IN (3.1 miles NNW)
Stringtown, IN (3.1 miles WNW)
Mechanicsville, IN (3.4 miles NW)
Harwood, IN (3.4 miles W)
Country Club Meadows, IN (3.6 miles WNW)
Kratzville, IN (4.1 miles WNW)
McCutchanville, IN (4.3 miles N)
Stevenson, IN (4.5 miles ENE)

Indiana Census Data Comparison Tool

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